4x^4-x^2+8=0

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Solution for 4x^4-x^2+8=0 equation:


Simplifying
4x4 + -1x2 + 8 = 0

Reorder the terms:
8 + -1x2 + 4x4 = 0

Solving
8 + -1x2 + 4x4 = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
4 the coefficient of the squared term: 

Divide each side by '4'.
2 + -0.25x2 + x4 = 0

Move the constant term to the right:

Add '-2' to each side of the equation.
2 + -0.25x2 + -2 + x4 = 0 + -2

Reorder the terms:
2 + -2 + -0.25x2 + x4 = 0 + -2

Combine like terms: 2 + -2 = 0
0 + -0.25x2 + x4 = 0 + -2
-0.25x2 + x4 = 0 + -2

Combine like terms: 0 + -2 = -2
-0.25x2 + x4 = -2

The x term is -0.25x2.  Take half its coefficient (-0.125).
Square it (0.015625) and add it to both sides.

Add '0.015625' to each side of the equation.
-0.25x2 + 0.015625 + x4 = -2 + 0.015625

Reorder the terms:
0.015625 + -0.25x2 + x4 = -2 + 0.015625

Combine like terms: -2 + 0.015625 = -1.984375
0.015625 + -0.25x2 + x4 = -1.984375

Factor a perfect square on the left side:
(x2 + -0.125)(x2 + -0.125) = -1.984375

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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